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a
2π
b
10π
c
8π
d
5π
answer is B.
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Detailed Solution
fx=sin3x2+cos5x5 The period of sin3x is 2πSo, the period of sin3x2 is 2π112=4π So, the period of sin3x2 is2π.The period of cos5x is 2π.So, the period of cos5x5 is 2π15=10π.So, the period of cos5x2 is 5π.Now, period ot fx=LCM of 2π,5π=10π