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a
2π
b
10π
c
8π
d
5π
answer is B.
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Detailed Solution
fx= sin3x2+cos5x5the period of sin3x is 2π since sin32π+x=sin3x ⇒the period of sin3x2= 2π12 =4π if fx period is p then fax+b period is pa ⇒ so the period of sin3x2 is 2π the period of cos5x is 2π so the period of cos5x5 is 2π15= 10π so the period of cos5x2 is =5πso the period of fx = LCM of2π,5π =10π