Q.
Period of the function sin3x2+cos5x5 is
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a
2π
b
10π
c
8π
d
5π
answer is B.
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Detailed Solution
Period of sinx=2π⇒ period of sin3x=2π period of sin3x=π⇒ period of sin3x2=2π period of cos5x=2π⇒ period of cos5x=π⇒ period of cos5x5∣=5πThe required period is LCM of 2π and 5π is 10π
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