Q.

Period of the function sin3x2+cos5x5 is

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a

2π

b

10π

c

8π

d

5π

answer is B.

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Detailed Solution

Period of sinx=2π⇒ period of sin3x=2π period of sin3x=π⇒ period of sin3x2=2π period of cos5x=2π⇒ period of cos5x=π⇒ period of cos5x5∣=5πThe required period is LCM of 2π and 5π  is 10π
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