Q.

Period tanθ(1+sec2θ) (1+sec4θ)(1+sec8θ) is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

π2

b

π

c

2π

d

π8

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

tanθ1+sec2θ(1+sec4θ)(1+sec8θ) =tanθ1+cos2θcos2θ1+cos4θcos4θ1+cos8θcos8θ =sinθcosθ2cos2θcos2θ2cos22θcos4θ2cos24θcos8θ =sin8θcos8θ=tan8θ period is π8
Watch 3-min video & get full concept clarity
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
whats app icon
Period tanθ(1+sec2θ) (1+sec4θ)(1+sec8θ) is