Questions
The perpendicular distance from to the line passing through the point where the point bisects the portion of the line intercepted between the axes.
detailed solution
Correct option is D
The equation of the line whose portion intercepted between the axes bisected by x1,y1 is xx1+yy1=2 Hence the equation of the line whose portion intercepted between the axes at P(2,1) is x2+y=2 Rewrite the equation as x+2y−4=0 The perpendicular distance from a point Px1,y1 to the line ax+by+c=0 is ax1+by1+ca2+b2 The perpendicular distance from a point (1,3) to the line x+2y−4=0 is 1+23−41+4=35=355Talk to our academic expert!
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If the equation of the locus point equidistant from the points and is then the value of c is
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