Download the app

Questions  

The perpendicular distance from 1,3  to the line passing through the point P2,1 where the point P2,1 bisects the portion of the line intercepted between the axes.

a
154
b
45
c
35
d
355

detailed solution

Correct option is D

The equation of the line whose portion intercepted between the axes bisected by x1,y1 is xx1+yy1=2 Hence the equation of the line whose portion intercepted between the axes at P(2,1) is x2+y=2 Rewrite the equation as x+2y−4=0 The perpendicular distance from a point Px1,y1 to the line ax+by+c=0 is ax1+by1+ca2+b2 The perpendicular distance from a point (1,3) to the line x+2y−4=0 is 1+23−41+4=35=355

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

If the equation of the locus point equidistant from the points a1,b1 and a2,b2 is a1a2x+b1b2y+c=0, then the value of c is 


phone icon
whats app icon