Q.

The perpendicular distance of the point (2,4,-1) from line x+51=y+34=z−6−9 is

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answer is 7.

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Detailed Solution

A=(2,4,−1),Any point on the line P=(t−5, 4t−3, −9t+6)Let P be the foot of the perpendicular of AAP  is perpendicular to given line.Use formula a1a2+b1b2+c1c2=0 , t = 1point P(-4,1,-3)find distance between PandA
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The perpendicular distance of the point (2,4,-1) from line x+51=y+34=z−6−9 is