A person is known to speak truth 3 out of 4 times. He throws a dice and responds that it is a six. Then the probability that it is actually a six is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

answer is 0.375.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

LetE = the event that A reports it is six E1 = six turns up when a dice is thrown E2 = six does not turns up when a dice is thrown Probability that six actually showed up if A reported that of was six =PE1/EPE1/E=PE1∩EP(E)=PE1⋅PE/E1PE1⋅PE/E1+PE2⋅PE/E2PE/E1=Probability that the person reports six when it actually showed PE/E2= Probability that the person reports six when it did not show six = Probability that he lies =1−34=14 also PE1=16 and PE2=56PE1/E=16⋅3416⋅34+56⋅14=38

Watch 3-min video & get full concept clarity