First slide

Combinations

Question

A person wishes to make up as many different parties of 10 as he can out of 20 friends, each party consisting of the same number. The number of ways that the same man is found in different parties is

Easy

A

380
B

19
C

90378
D

92378

Solution

The number of ways that the same man is found in different parties is _{$=^{19} c_{9} = 92378$}

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