Q.

A plane passes through (2,3,-1) and is perpendicular to the line having dr's (3,-4,7). The perpendicular distance from the origin to this plane is K74 then k is equal to

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answer is 13.

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Detailed Solution

Equation of the plane 3(x−2)−4(y−3)+7(z+1)=0⇒3x−4y+7z+13=0Perpendicular distance from origin =139+16+49=1374The equation of the plane is x4+y9+z3=1
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A plane passes through (2,3,-1) and is perpendicular to the line having dr's (3,-4,7). The perpendicular distance from the origin to this plane is K74 then k is equal to