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$A plane which is perpendicular to two planes 2 x - 2 y + z = 0 and x - y + 2 z = 4 passes through$
$(1, - 2, 1) . The distance of the plane from the point (1,$ $2, 2) is$

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Correct option is D

The equation of the plane passing through the point (1,−2,1) and perpendicular to the planes 2x−2y+z=0 and x−y+2z=4 is given by x−1y+2z−12−211−12=0 or x+y+1=0Its distance from the point (1, 2,2) is 1+2+12=22

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A plane which is perpendicular to two planes 2x−2y+z=0 and x−y+2z=4 passes through (1,−2,1). The distance of the plane from the point (1, 2,2) is

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$A plane which is perpendicular to two planes 2 x - 2 y + z = 0 and x - y + 2 z = 4 passes through$
$(1, - 2, 1) . The distance of the plane from the point (1,$ $2, 2) is$