The plane x2+y3+z1=1 meet the co-ordinate axis at the points A, B, C respectively then the area bounded by the triangle ABC is

In the problem A(2,0,0), B(0,3,0), C(0,0,1)  Area of Δ ABC=12Δx 2+Δy 2+Δz 2  where Δx=030001111=3Δy=200001111=2Δz=033200111=|(−6)|=6Required area = 129+4+36=72