Point (1 ,2) and (-2 , 1) are
on the same side of the line 4x + 2y =1
on the line 4x+2y=1
on the opposite side of 4x+2y=1
none of these
Let L=4x+2y−1
we have , L>0 for x=1,y=2
and , L<0 for x=−2,y=1
Hence, the two points (1, 2) and (-2, 1) are on the opposite side of the line L = 0