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Point (1 ,2) and $(- 2, 1)$ are

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on the same side of the line 4x + 2y =1

on the line 4x+2y=1

on the opposite side of 4x+2y=1

none of these

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detailed solution

Correct option is C

Let L=4x+2y−1we have , L>0 for x=1,y=2 and , L<0 for x=−2,y=1 Hence, the two points (1, 2) and (-2, 1) are on the opposite side of the line L = 0

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Point (1 ,2) and (-2 , 1) are

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Point (1 ,2) and $(- 2, 1)$ are