A point on the curve y=x3-3x+5 at which the tangent line is parallel to y=-2 x is

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(1, 3)

(0, 5)

13,5-839

12,0

answer is C.

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Detailed Solution

Since y'(x)=3x2-3 so by the condition of parallelism 3x2-3=-2x=±13If x=13, then y=133-33+5=5-833=5-839

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