The point diametrically opposite to the pointP (1, 0) on the circle x2+y2+2x+4y−3=0, is

The coordinate of the centre of the circle are(-1,-2). Let Q (a, b) be diametrically opposite to P. Then,mid-point of PQ is the centre of the circle.∴ a+12=−1 and b+02=−2⇒a=−3 and b=−4Hence, required point is (- 3, - 4).