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The point diametrically opposite to the point
$P (1, 0)$ on the circle $x^{2} + y^{2} + 2 x + 4 y - 3 = 0,$ is

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(-3,-4)

(3, 4)

(3, -4)

(-3, 4)

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detailed solution

Correct option is A

The coordinate of the centre of the circle are(-1,-2). Let Q (a, b) be diametrically opposite to P. Then,mid-point of PQ is the centre of the circle.∴ a+12=−1 and b+02=−2⇒a=−3 and b=−4Hence, required point is (- 3, - 4).

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The point diametrically opposite to the pointP (1, 0) on the circle x2+y2+2x+4y−3=0, is

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Ready to Test Your Skills?

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The point diametrically opposite to the point
$P (1, 0)$ on the circle $x^{2} + y^{2} + 2 x + 4 y - 3 = 0,$ is