The point from which the tangents to the circles x2+y2−8x+40=05x2+5y2−25x+80=0x2+y2−8x+16y+160=0are equal in length, is

The required point is the radical centre of the three given circles. The radical axes of these three circles taken in pairs are:  3x−24=0,16y+120=0 and  −3x+16y+80=0 Solving any two of these three equations, we getx=8,y=−152Hence, the required point is (8, -15/2)