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Questions  

The point from which the tangents to the circles 

x2+y28x+40=05x2+5y225x+80=0x2+y28x+16y+160=0

are equal in length, is

a
(8, 15/2)
b
(- 8, 15/2)
c
(8, -15/2)
d
none of these

detailed solution

Correct option is C

The required point is the radical centre of the three given circles. The radical axes of these three circles taken in pairs are:  3x−24=0,16y+120=0 and  −3x+16y+80=0 Solving any two of these three equations, we getx=8,y=−152Hence, the required point is (8, -15/2)

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