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$The point of intersection of the line passing through (0, 0, 1) and intersecting the lines x + 2 y + z = 1,$
$- x + y - 2 z = 2 and x + y = 2, x + z = 2 with x y plane is$

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53,−13,0

(1,1,0)

23,−13,0

−53,13,0

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detailed solution

Correct option is A

Equation of line. x+2y+z−1+λ(−x+y−2z−2)=0-----ix+y−2+μ(x+z−2)=0----ii(0,0,1) lies on it ⇒λ=0,μ=−2 For point of intersection, z=0 and solve (i) and (ii).

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The point of intersection of the line passing through (0,0,1) and intersecting the lines x+2y+z=1,−x+y−2z=2 and x+y=2,x+z=2 with xy plane is

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Ready to Test Your Skills?

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$The point of intersection of the line passing through (0, 0, 1) and intersecting the lines x + 2 y + z = 1,$
$- x + y - 2 z = 2 and x + y = 2, x + z = 2 with x y plane is$