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The point of intersection of lines $2 x + 3 y + 4 = 0$ and $6 x - y + 12 = 0$ is

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Correct option is B

Eliminate y 2x+3y+4+36x−y+12=02x+3y+4+18x−3y+36=020x+40=0x=−2Substitute x=-2 in the equation 2x+3y+4=0 2−2+3y+4=03y=0y=0Therefore, the point of intersection is −2,0

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The point of intersection of lines 2x+3y+4=0 and 6x−y+12=0 is

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The point of intersection of lines $2 x + 3 y + 4 = 0$ and $6 x - y + 12 = 0$ is