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Point of intersection of pair of lines $a {(x - α)}^{2} + 2 h (x - α) (y - β) + b {(y - β)}^{2} = 0$ is

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(0,0)

α,β

(−α,−β)

(−α,β)

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detailed solution

Correct option is B

line passing through (α,β)

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Point of intersection of pair of lines a(x−α)2+2h(x−α)(y−β)+b(y−β)2=0 is

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Point of intersection of pair of lines $a {(x - α)}^{2} + 2 h (x - α) (y - β) + b {(y - β)}^{2} = 0$ is