Q.
At the point of intersection of the rectangular hyperbolaxy=c2 and the parabola y2=4ax tangents to the rectangular hyperbola and the parabola make angles θ and ϕ , respectively with x -axis, then
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Detailed Solution
Let x1,y1 be point of intersection. ⇒ y12=4ax1,x1y1=c2 For y2=4axmTx1,y1=2ay1=tanϕ For xy=c2,MTx1,y1=−y1x1=tanθ So tanθtanϕ=−y122ax1=−4ax12ax1=−2 So θ=tan−1(−2tanϕ)
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