At the point of intersection of the rectangular hyperbolaxy=c2 and the parabola y2=4ax tangents to the
rectangular hyperbola and the parabola make angles θ and ϕ , respectively with x -axis, then
Let x1,y1 be point of intersection.
⇒ y12=4ax1,x1y1=c2 For y2=4ax
mTx1,y1=2ay1=tanϕ For xy=c2,MTx1,y1=−y1x1=tanθ
So tanθtanϕ=−y122ax1=−4ax12ax1=−2 So θ=tan−1(−2tanϕ)