The point of the line x−21=y+3−2=z+5−2  at a distance of 6 from the point (2, - 3, - 5) is

Direction cosines of the given line are 13,−23,−23Hence, the equation of line can be a point in the formx−21/3=y+3−2/3=z+5−2/3=rTherefore, any point on the line is 2+r3,−3−2r3,−5−2r3, where r=±6Points are (4, -7, - 9) and (0, 1, -1)