Point M moved on the circle (x−4)2+(y−8)2=20.Then it broke away from it and moving along a tangent to the circle cut the x-axis at point (-2,0). The coordinates of the point on the circle at which the moving point broke away is
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a
(42/5,36/5)
b
(−2/5,44/5)
c
(6,4)
d
(2,4)
answer is B.
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Detailed Solution
x2+y2−8x−16y+60=0 -----(i) Equation of chord of contact from (−2,0) is −2x−4(x−2)−8y+60=0 or 3x+4y−34=0------(ii) Solving (i) and (ii), we get x2+34−3x42−8x−1634−3x4+60=0 or 16x2+1156−204x+9x2−128x−2176+192x+960=0 or 5x2−28x−12=0 or (x−6)(5x+2)=0 or x=6,−25 Therefore, the points are (6,4) and (−2/5,44/5).
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Point M moved on the circle (x−4)2+(y−8)2=20.Then it broke away from it and moving along a tangent to the circle cut the x-axis at point (-2,0). The coordinates of the point on the circle at which the moving point broke away is