The point P (a$$, $$b) lies on the straight line $$3x$$ $$+$$ $$2y$$ $$=$$ $$13$$ and the point Q (b$$, $$a) lies on the straight line $$4x$$ $$-$$ y $$=$$ $$51$$ then the equation of the line PQ is

Question

The point P (a$$, $$b) lies on the straight line $$3x$$ $$+$$ $$2y$$ $$=$$ $$13$$ and the point Q (b$$, $$a) lies on the straight line $$4x$$ $$-$$ y $$=$$ $$51$$ then the equation of the line PQ is

Infinity Learn · Accepted Answer

It is given that points P (a$$, $$b) and Q (b$$, $$a) lie on the lines $$3x$$ $$+$$ $$2y$$ $$=$$ $$13$$ and $$4x$$ $$-$$ y $$=$$ $$5$$ respectively.∴ $$3a+2b=13$$ and $$4b$$−$$a=5$$⇒$$a=3$$,$$b=2Thus$$, the coordinates of P and Q are (3$$, $$2) and (2$$, $$3) respectively. So, the equation of line PQ is       y−$$2=3$$−$$22$$−$$3(x$$−$$3)$$ or, $$x+y=5$$

The point $P (a, b)$ lies on the straight line $3 x + 2 y = 13$ and the point $Q (b, a)$ lies on the straight line $4 x - y = 51$ then the equation of the line $P Q$ is

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The point P (a, b) lies on the straight line 3x + 2y = 13 and the point Q (b, a) lies on the straight line 4x - y = 51 then the equation of the line PQ is

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The point $P (a, b)$ lies on the straight line $3 x + 2 y = 13$ and the point $Q (b, a)$ lies on the straight line $4 x - y = 51$ then the equation of the line $P Q$ is