A point P lies on the ellipse $$(y$$−$$1)264+(x+2)249=1$$ . If distance of P from one focus is $$8$$, then its distance from other focus is

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Question

$A point P lies on the ellipse \frac{(y - 1)^{2}}{64} + \frac{(x + 2)^{2}}{49} = 1 . If distance of P from one focus is 8, then its distance from other focus is$

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Solution

$For given ellipse a = 8 and b = 7 .$
$Let P be any point on the ellipse, then S P + S^{'} P = 2 b .$
$Given S P = 8 then S^{'} P = 6$

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