Q.
The point P (2,1) is translated parallel to the line L: x-y = 4 by 23 units. If the new point Q lies in the third quadrant, then the equation of the line passing through Q and perpendicular to L is
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a
x+y=2-6
b
x+y=3-36
c
x+y=3-26
d
2x+2y=1-6
answer is C.
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Detailed Solution
Q=2+2312,1+23.12; 2-6, 1-6required line equationy-1-6=-1x-2-6x+y=1-6+2-6=3-26
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