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Q.

The point P (2,1) is translated parallel to the line L: x-y = 4 by 23 units. If the new point Q lies in the third quadrant, then the equation of the line passing through Q and perpendicular to L is

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a

x+y=2-6

b

x+y=3-36

c

x+y=3-26

d

2x+2y=1-6

answer is C.

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Detailed Solution

Q=2+2312,1+23.12;   2-6, 1-6required line equationy-1-6=-1x-2-6x+y=1-6+2-6=3-26
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