The point P (1, 1) is translated parallel to 2x=y in the first quadrant through a unit distance. The coordinates of the new position of P are
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a
(1±25,1±15)
b
(1±15,1±25)
c
(15,25)
d
(25,15)
answer is B.
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Detailed Solution
tanθ=2 ∴ sinθ=25,cosθ=15Let new co−ordinate is (x1,y1)∴ x1−1cosθ=y1−1sinθ=±1∴ x1=1±cosθ, y1=1±sinθx1=1±15,y1=1±25Hence, new position of P are (1±15,1±25)