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Q.

The point P (1, 1) is translated parallel to 2x=y in the first quadrant through a unit distance. The coordinates of the new position of P are

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a

(1±25,1±15)

b

(1±15,1±25)

c

(15,25)

d

(25,15)

answer is B.

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Detailed Solution

tanθ=2 ∴     sinθ=25,cosθ=15Let  new  co−ordinate  is  (x1,y1)∴          x1−1cosθ=y1−1sinθ=±1∴  x1=1±cosθ,  y1=1±sinθx1=1±15,y1=1±25Hence,  new  position  of  P  are  (1±15,1±25)
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