Q.

A point on the straight line, 3x+5y=15 which is equidistant from the coordinate axes will lie only in

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a

4th quadrant

b

1st quadrant

c

1st and 2nd quadrant

d

1st, 2nd and 4th quadrant

answer is C.

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Detailed Solution

Given equation of line is 3x+5y=15..........(1)Clearly, a point of the line (1) which is equidistance from X and Y-axes will lie on the line either y=x or y=-xy=x3x+5y=15 on solving 158,158y=-x3x+5y=15 on solving −152,152
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