First slide

Introduction to 3-D Geometry

Question

$The points A(2,9,12), B(1,8,3),C(-2,11,8), D(-1,12,2) forms$

Easy

A

A parallelogram
B

A Rhombus
C

A rectangle
D

A square

Solution

$The given points are A(2,9,12), B(1,8,3),C(-2,11,8), D(-1,12,2) AB= \sqrt{1 + 1 + 81} = \sqrt{83} AD = \sqrt{9 + 9 + 100} = \sqrt{118} Adjacent sides are not equal, means the figure formed by the above points is not square and not Rhombus AC = \sqrt{16 + 4 + 16} = 6 BD = \sqrt{4 + 16 + 1} = \sqrt{18} Diagonals are not equal, means the figure formed by the given points is not rectangle and not square Hence, the figure formed by the given points is Parallelogram .$

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