Questions
The points of contact of tangents to the circle which are inclined at an angle of to the axis are
detailed solution
Correct option is D
The equation of a tangent of slope m to the circle x2+y2=a2 is y=mx±a1+m2 and the coordinates of point of contact are ∓am1+m2,±a1+m2 Here, a=5 and m=tan 30=1/3.So, the coordinates of the points of contact are ∓52,±532Talk to our academic expert!
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