Questions
a
(± 4/3−2)
b
(± 11/3, 1)
c
(0, 0)
d
(± 4/3, 2)
detailed solution
Correct option is D
Differentiating the given curve w.r.t. x, we get3y2dydx + 6x = 12dydx ⇒ dydx = − 2xy2−4 At point where the tangent(s) is (are) vertical, dydx is not defined, i.e. at those points.y2−4=0⇒y=±2 When y=2,8+3x2=12(2)⇒3x2=16⇒x=±43 when y=−2,−8+3x2=−24⇒3x2=−16. This is not possible Thus, the required points are (±4/3,2)Talk to our academic expert!
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