The points (p, 2−2p),(1−p, 2p) and (−4−p, 6−2p) are collinear. Then p=

A(p, 2−2p),B(1−p, 2p),C(−4−p, 6−2p) are collinear ⇒ΔABC=0⇒12|2p−12−4p2p+4−4|=0⇒|(−8p+4)−(2−4p)(2p+4)|=0⇒|−8p+4+12p+8p2−8|=0⇒|8p2+4p−4|=0,⇒|2p2+p−1|=0⇒2p2+2p−p−1=0 ⇒2p(p+1)−1(p+1)=0                     ⇒(2p−1)(p+1)=0                ∴p=−1  or  12