First slide

Cartesian plane

Question

The points (–2, –1), (1, 0), (4, 3), (1, 2) taken in order form

Easy

A

a parallelogram
B

a square
C

a rhombus
D

a rectangle

Solution

$A (- 2, - 1), B (1, 0), C (4, 3), D (1, 2)$ , $A + C = B + D$ , Slope of BC= 1 , slope of $A B = \frac{1}{3}, \bar{A B} ⊥_{r} \bar{B C}$
$A B = \sqrt{9 + 1} = \sqrt{10}, B C = \sqrt{9 + 9} = \sqrt{18} ∴ A B \neq B C$

$∴$ A,B,C,D forms a parallelogram

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