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Random variable and probability distribution
Question
In a Poisson distribution,
P
(
x
=
0
)
=
P
(
x
=
1
)
=
k
then
k
=
Easy
A
1
B
1
e
C
e
D
e
Solution
e
−
λ
λ
0
0
!
=
e
−
λ
λ
1
1
!
⇒
λ
=
1
k
=
e
−
1
1
1
!
=
1
e
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