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The polar coordinates equivalent to $(- 3, \sqrt{3})$ are

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(23,π6)

(−23,5π6)

(23,7π6)

(23,5π6)

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detailed solution

Correct option is D

r=x2+y2=9+3=23α=tan−1|y||x|α=tan−1(33)α=tan−1(13)=π6Point (−3,3) lies in the second quadrant. ∴θ=π−α=π-π6=5π6So, polar coordinates are (23,5π6)

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The polar coordinates equivalent to (−3,3) are

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The polar coordinates equivalent to $(- 3, \sqrt{3})$ are