Polynomial P(x) contains only terms of odd degree. When P(x) is divided by (x - 3), the remainder is 6. If P(x) is divided by (x2 - 9), then the remainder is g(x). Then the value of g(2) is ________.

As P(x) is an odd functionHence, P(−x)=−P(x)⇒P(−3)=−P(3)=−6Let P(x)=Qx2−9+ax+b(where Q is quotient and (ax + b) = g(x) = remainder)Now P(3)=3a+b=6               …. (1)        P(−3)=−3a+b=−6    ….. (2)Hence, b = 0 and a = 2Hence, g(x) = 2x ⇒g(2)=4