The population P = P(t) at time ‘t’ of a certain species follows the differential equationdPdt=0.5P−450 . If P0=850then the time at which population becomes zero is:
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a
12loge18
b
loge9
c
loge18
d
2loge18
answer is D.
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Detailed Solution
The given differential equation dPtdt=Pt−9002integrate both sides ∫0tdPtPt−900=∫0tdt2lnPt−9000t=t20tlnPt−900−lnP0−900=t2lnPt−900−ln50=t2When population becomes zeroit gives ln900−ln50=t2t=2ln90050=2ln18therefore, t=2ln18