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For a positive integer n, let  a(n)=1+12+13+14++12n1. Then 

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a
a (100) < 100
b
a (100) > 100
c
a (200) < 100
d
none of these

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detailed solution

Correct option is A

a(n)=1+12+13+14+⋯+17+18+⋯+115+⋯+12n−1+12n−1+1+⋯+12n−1<1+22+44+88+⋯+2n−12n−1=nThus, a (100) < 100.


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