The positive integer value of n> 3 satisfying the equation 1sinπn=1sin2πn+1sin3πn is
1sinπn−1sin3πn=1sin2πn⇒sin3πn−sinπnsinπnsin3πn=1sin2πn⇒2sinπncos2πnsin2πnsinπnsin3πn=1⇒sin4πn=sin3πn⇒4πn+3πn=π⇒n=7