First slide
Introduction to Determinants
Question

For positive numbers x, y, and z the numerical value of the determinant  |1logxylogxzlogyx1logyzlogzxlogzy1| is:

Easy
Solution

|1logxylogxzlogyx1logyzlogzxlogzy1| 

=(1logxylogyz)logxy(logyxlogzxlogyz)+logxz(logyxlogxylogzx)

=(11)(1logxylogyx)+(logxzlogzx1)=0 {sincelogxylogyx=1}

 

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