Questions
A possible value of is
detailed solution
Correct option is D
14sin−1638=θsin4θ=6382tan2θ1+tan22θ=638631+tan22θ=16tan2θ63tan22θ−16tan2θ+63=0Use the quadratic formula for It gives 2tanθ1−tan2θ=963 or 7637tan2θ−1+263tanθ=0tanθ=−263±252+19614=−263±44814=−67±8714=17Talk to our academic expert!
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Let and then the value of is
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