Q.

A possible value of   istan14sin−1638

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a

122

b

7−1

c

22−1

d

17

answer is D.

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Detailed Solution

14sin−1638=θsin4θ=6382tan2θ1+tan22θ=638631+tan22θ=16tan2θ63tan22θ−16tan2θ+63=0Use the quadratic formula for It gives     2tanθ1−tan2θ=963   or   7637tan2θ−1+263tanθ=0tanθ=−263±252+19614=−263±44814=−67±8714=17
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