Primitive of $$($$$$cos$$⁡x−$$sin$$⁡$$x)15$$−$$sin$$⁡$$2x$$ is equal to

Correct option is 2sin−1sinx+cosx4+c

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$Primitive of \frac{(\cos x - \sin x)}{\sqrt{15 - \sin 2 x}} is equal to$

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detailed solution

Correct option is B

I=∫cosx−sinxdx15−sin2x Put sin⁡x+cos⁡x=t(cos⁡x−sin⁡x)dx=dtsin⁡x+cos⁡x=t1+2sin⁡xcos⁡x=t2sin⁡2x=t2−1I=∫dt15−t2−1I=∫dt15−t2−1=sin−1⁡t4+c=sin−1⁡sin⁡x+cos⁡x4+c

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Primitive of (cos⁡x−sin⁡x)15−sin⁡2x is equal to

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$Primitive of \frac{(\cos x - \sin x)}{\sqrt{15 - \sin 2 x}} is equal to$