First slide
Methods of integration
Question

The primitive of 1(xa)3/2(bx)1/2 is

 

Moderate
Solution

putting xa=(1/t) we have dx=1/t2dt

 and the given integral can be written as 

1t2dt(1/t)3/2ba1t1/2=dt(ba)t1

=2(ba)t1ba+C=2baba(xa)xa+C=2abbxxa+C

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