Principal argument of z=i−1i1cos2π7+sin2π7 is
π28
3π28
17π28
19π28
i1−cos2π7+sin2π7
=2isin2π7+2sinπ7cosπ7=2sinπ7cosπ7+isinπ7
Also , i−1=2−12+i2
=2cos3π4+isin3π4
∴ z=22sinπ7cos3π4−π7+isin3π4−π7
=22sinπ7cos17π28+isin17π28
Thus , arg(z)=17π28.