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Questions  

The principal value of ‘θ’ for which 2Tan1cosθ=Tan12cosceθ

a
π4
b
π6
c
π3
d
π2

detailed solution

Correct option is A

We have 2Tan-1cosθ=Tan-12cosecθ ⇒Tan-12cosθ1-cos2θ=Tan-12sinθ⇒Tan-12cosθ1-cos2θ=Tan-12sinθ⇒2cosθsin2θ=2sinθ⇒cotθ=1⇒θ=π4

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