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Q.

The probabilities of three events A,B and C are given by P(A)=0.6,P(B)=0.4 and P(C)=0.5. If P(A∪B)=0.8,P(A∩C)=0.3,P(A∩B∩C)=0.2,P(B∩C)=β and P(A∪B∪C)=α where 0.85≤α≤0.95, then β lies in the interval :

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a

0.20,  0.25

b

0.25,  0.35

c

0.35,  0.36

d

0.36,  0.40

answer is B.

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Detailed Solution

P(A∪B∪C)=P(A)+P(B)+P(C)-P(A∩B)-P(B∩C)-P(C∩A)+P(A∩B∩C)⇒α=1.2-β0.85≤α≤0.95⇒0.85≤1.2-β≤0.95  ∣⇒0.25≤β≤0.35
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