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The probability that in a family of five members, exactly two members have birthday on Sunday is
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a
12×53/75
b
10×62/75
c
25
d
10×63/75
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Correct option is D
A person can have his/her birthday on any one of the seven days of the week. So 5 persons can have their birthdays in 75 ways. Out of 5, three persons can have their birthdays on days other than Sundays in 63 ways and other 2 on Sundays. Hence, the required probability is 5C2×6375=10×6375 (Note that 2 persons can be selected out of 5 in 5C2 ways.)Similar Questions
The odd against an event are 5 to 2 and the odds in favour of another disjoint event are 3 to 5. Then the probability that atleast one of the events will happen is
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