First slide

Theorems of probability

Question

The probability of getting a number between 1 and 100 which is divisible by 1 and itself only is

Easy

A

$\frac{1}{4}$
B

$\frac{1}{2}$
C

$\frac{3}{4}$
D

$\frac{25}{98}$

Solution

Number of primes which are less than 100 are ‘25’
$∴ n (A) = 25_{c_{_{1}}}, n (S) = 98_{c_{_{1}}}$
$∴ P (A) = \frac{n (A)}{n (s)} = \frac{25}{98}$

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