First slide

Theorems of probability

Question

The probability of getting a total of 9 in a single throw of two dice is

Easy

A

$\frac{1}{9}$
B

$\frac{2}{9}$
C

$\frac{1}{3}$
D

$\frac{4}{9}$

Solution

$E = \{(4, 5), (5, 4), (3, 6), (6, 3)\} ∴ P (E) = \frac{n (E)}{n (S)} = \frac{4}{36} = \frac{1}{9}$

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