First slide

Theorems of probability

Question

The probability of getting a total of 10 in a single throw of two dice is

Easy

A

$\frac{1}{9}$
B

$\frac{1}{12}$
C

$\frac{1}{6}$
D

$\frac{5}{36}$

Solution

$n (S) = 6^{2} = 36$
$E = S u m 10 = {(4, 6), (6, 4), (5, 5)}$

$∴ n (E) = 3$

$P (E) = \frac{n (E)}{n (S)} = \frac{3}{36} = \frac{1}{12}$

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