The probability that an individual suffers a bad reaction from an injection is 0.001. The probability that out of 2000 individuals more than 2 suffer a bad reaction is

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5e2

1−5e2

1−4e2

4e2

answer is B.

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Detailed Solution

p=0.001,n=2000 λ=np=2 P(X>2)=1−[P(X=0)+P(X=1)+P(X=2)] =1−[1+211!+222!]e−2 =1−5e2

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