First slide

Theorems of probability

Question

The probability that a leap year will have 53 Sundays is

Easy

A

$\frac{1}{7}$
B

$\frac{2}{7}$
C

$\frac{5}{7}$
D

$\frac{6}{7}$

Solution

In leap year 366 days (52 weeks+2days)
S={(M,T),(T,W),(W,Th),(Th,F),(F,Sat),(Sat,Sun),(Sun,M)}

$∴ n (S) = 7$

53 Sundays = 52 Sundays +1 Sunday

$∴ n (E) = 2$

$∴ P (E) = \frac{2}{7}$

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